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app.js

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  • exercising for code.py 1.72 KiB
    Python 3.7.1 (v3.7.1:260ec2c36a, Oct 20 2018, 03:13:28) 
    [Clang 6.0 (clang-600.0.57)] on darwin
    Type "help", "copyright", "credits" or "license()" for more information.
    >>> #연습문제 1. 1부터 100까지 출력
    >>> for i in range(1,101)
    SyntaxError: invalid syntax
    >>> for i in range(1,101):
    	print(i)
    
    	
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    >>> #문제2. 5의 배수의 총합
    >>> sum = 0
    >>> for i range(1,100):
    	
    SyntaxError: invalid syntax
    >>> for i in range(1,1000):
    	if i%5 == 0 :
    		sum=sum +i
    
    		
    >>> print(sum)
    99500
    >>> sum2=0
    >>> for i in range(1,50):
    	if i%5 == 0 :
    		sum2= sum2+i
    
    		
    >>> print(sum2)
    225
    >>> #문제3. 학급의 평균 점수
    >>> A = [70,60,55,75,95,90,80,80,85,100]
    >>> sum = 0
    >>> for i in A:
    	sum = sum + A[i]
    
    	
    Traceback (most recent call last):
      File "<pyshell#25>", line 2, in <module>
        sum = sum + A[i]
    IndexError: list index out of range
    >>> for i in A:
    	sum = sum +i
    
    	
    >>> print(sum)
    790
    >>> count = 0
    >>> for i in A:
    	count = count+1
    print(sum/count)
    SyntaxError: invalid syntax
    >>> count = 0
    >>> sum =0
    >>> for i in A:
    	count = count+1
    	sum = sum + i
    
    	
    >>> print(sum/count)
    79.0
    >>> #문제4. 각 혈액형별 학생수의 합계를 구하시오.
    >>> B = ['A','B','A','O','AB','AB','O','A','B','O','B','AB']
    >>> a=0
    >>> b=0
    >>> ab=0
    >>> o=0
    >>> for s in B:
    	if s=='A':
    		a=a+1
    	elif s==
    	
    SyntaxError: invalid syntax
    >>> for s in B:
    	if s=='A':
    		a=a+1
    	elif s=='B':
    		b=b+1
    	elif s=='AB':
    		ab=ab+1
    	else:
    		o=o+1
    
    		
    >>> print(a,b,ab,o)
    3 3 3 3
    >>>